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Matthew 22:26-28
New American Standard Bible 1995
Matthew 22:26-28
New American Standard Bible 1995
26 so also the second, and the third, down to the seventh. 27 Last of all, the woman died. 28 In the resurrection, therefore, whose wife of the seven will she be? For they all had married her.”
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New American Standard Bible 1995 (NASB1995)
New American Standard Bible®, Copyright © 1960, 1971, 1977, 1995 by The Lockman Foundation. All rights reserved.